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Assuming that no equilibria other than dissolution are involved, calculate the concentrations of ions in a saturated solution of each of the following (see Appendix J for solubility products).

a) Ca(OH)2
b) Ag2S
c) Fe(OH)3
d) PbCl2

User Trent
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Final answer:

To calculate the concentrations of ions in a saturated solution, we can use the solubility product constants and the dissociation equations of the compounds. The concentrations of Ca2+, OH-, Ag+, S2-, Fe3+, and Pb2+ can be calculated using the given solubility product constants. The equations and calculations are provided in the answer.

Step-by-step explanation:

When a compound dissolves in water, it dissociates into its respective ions. The concentrations of these ions can be calculated using the solubility product, which is a measure of the extent to which a compound dissolves in water. In order to calculate the concentrations, we can use the solubility product constants (Ksp) from Appendix J.

(a) Calculation for Ca(OH)2:

Ca(OH)2(s) → Ca2+(aq) + 2OH-(aq)

Ksp = [Ca2+][OH-]^2

Given the solubility product constant for Ca(OH)2 is 5.02 x 10^-5, we can solve for the concentrations of Ca2+ and OH-.

(b) Calculation for Ag2S:

Ag2S(s) → 2Ag+(aq) + S2-(aq)

Ksp = [Ag+]^2[S2-]

Given the solubility product constant for Ag2S is 8 x 10^-50, we can solve for the concentrations of Ag+ and S2-.

(c) Calculation for Fe(OH)3:

Fe(OH)3(s) → Fe3+(aq) + 3OH-(aq)

Ksp = [Fe3+][OH-]^3

Given the solubility product constant for Fe(OH)3 is 1.1 x 10^-39, we can solve for the concentrations of Fe3+ and OH-.

(d) Calculation for PbCl2:

PbCl2(s) → Pb2+(aq) + 2Cl-(aq)

Ksp = [Pb2+][Cl-]^2

Given the solubility product constant for PbCl2 is 1.6 x 10^-5, we can solve for the concentrations of Pb2+ and Cl-.

User Brynna
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