Final answer:
The equilibrium constant expression for the reaction is K = [CO][H₂] / [C][H₂O]. If more C is added, the concentrations of CO and H₂ will increase, while the concentrations of C and H₂O will decrease. If H₂O is removed, the equilibrium will shift to the left. If CO is added, the equilibrium will shift to the left. If the temperature is increased, the equilibrium will shift in the endothermic direction.
Step-by-step explanation:
(a) The expression for the equilibrium constant for the reversible reaction C(s) + H₂O(g) ⇌ CO(g) + H₂(g) is K = [CO][H₂] / [C][H₂O].
(b) If more C is added, according to Le Chatelier's principle, the equilibrium will shift to the right to relieve the stress. This means that the concentrations of CO and H₂ will increase, while the concentrations of C and H₂O will decrease.
(c) If H₂O is removed, the equilibrium will shift to the left to replace the lost reactant. This means that the concentrations of CO and H₂ will decrease, while the concentrations of C and H₂O will increase.
(d) If CO is added, the equilibrium will shift to the left to relieve the stress. This means that the concentrations of CO and H₂ will decrease, while the concentrations of C and H₂O will increase.
(e) If the temperature of the system is increased, the equilibrium will shift in the endothermic direction to absorb the additional heat. This means that the concentrations of CO and H₂ will increase, while the concentrations of C and H₂O will decrease.