Question

P₄​(s)+5O₂​(g)⟶P₄​O₁₀​(s),ΔG∘=−2697.0kJ/mol, what is the standard free energy change for the reaction? a) 2697.0 kJ/mol b) −539.4 kJ/mol c) 539.4 kJ/mol d) −2697.0 kJ/mol

Answer 1

The standard free energy change for the reaction P₄​(s) + 5O₂​(g) ⟶ P₄​O₁₀​(s) is -2697.0 kJ/mol.

Step-by-step explanation:

The standard free energy change for the reaction P₄​(s) + 5O₂​(g) ⟶ P₄​O₁₀​(s) is -2697.0 kJ/mol.

This value is given by the equation AG° = -RT ln K, where AG° represents the standard free energy change, R is the ideal gas constant, T is the temperature, and K is the equilibrium constant.

In this case, the value of AG° is -2697.0 kJ/mol, given in the question.