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Calculate [HgCl₄ 2−] in a solution prepared by adding 0.0200 mol of NaCl to 0.250 L of a 0.100-M HgCl₂ solution.

a) 0.100 M
b) 0.090 M
c) 0.110 M
d) 0.020 M

1 Answer

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Final answer:

The concentration of [HgCl₄ 2−] in the solution is 0.100 M.

Step-by-step explanation:

To calculate the concentration of [HgCl₄ 2−] in the solution, we first need to determine the molar amount of HgCl₂ in the solution.

The molar amount of HgCl₂ is calculated as follows:

0.250 L × 0.100 M = 0.025 mol HgCl₂

Next, we use the stoichiometry of the reaction to determine the molar amount of [HgCl₄ 2−] produced.

The stoichiometry of the reaction is 1:1, so the molar amount of [HgCl₄ 2−] is also 0.025 mol.

Finally, we calculate the concentration of [HgCl₄ 2−] in the solution:

0.025 mol ÷ 0.250 L = 0.100 M

User Hugh Mullally
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