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What is the average acceleration of a powerful motorcycle that accelerates from rest to 26.8 m/s (100 km/h) in only 3.90 s?

a) 4.72 m/s²
b) 6.88 m/s²
c) 8.21 m/s²
d) 10.67 m/s²

User Ben Stahl
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1 Answer

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Final answer:

The average acceleration of the motorcycle is 6.88 m/s². The motorcycle travels a distance of 52.19 meters in 3.90 seconds.

Step-by-step explanation:

The average acceleration of a motorcycle can be calculated by dividing the change in velocity by the change in time. In this case, the change in velocity is 26.8 m/s and the change in time is 3.90 s.

Using the formula: average acceleration = (final velocity - initial velocity) / time

Plugging in the values, we get: average acceleration = (26.8 m/s - 0 m/s) / 3.90 s = 6.88 m/s²

Therefore, the average acceleration of the motorcycle is 6.88 m/s².

To calculate the distance traveled by the motorcycle in that time, we can use the formula: distance = initial velocity * time + (1/2) * average acceleration * time²

Since the initial velocity is 0 m/s and the average acceleration is 6.88 m/s², and the time is 3.90 s, we can calculate:

distance = 0 m/s * 3.90 s + (1/2) * 6.88 m/s² * (3.90 s)² = 52.19 m

Therefore, the motorcycle travels a distance of 52.19 meters in 3.90 seconds.

User Klotz
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