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Give the coordination numbers and write the formulas for each of the following, including all isomers where appropriate:

a. Hexaaquairon(II) ion - [Fe(H₂O)₆]²⁺ - 6
b. Tetraamminechloronitrito-N-platinate(II) - [Pt(NH₃)₄(NO₂)Cl]²⁻ - 6
c. Diamminedichloroplatinum(II) - [Pt(NH₃)₂Cl₂] - 4
d. Pentaamminenitrosylcobalt(III) - [Co(NH₃)₅NO]²⁺ - 6

1 Answer

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Final answer:

The coordination numbers for the given complexes are determined by counting the number of points at which the ligands attach to the central metal ion. The central metal ions Co, Cu, Pt, Cr, Pd, and Zn in the respective complexes have coordination numbers of six, four, six, four, six, four, five, and four respectively.

Step-by-step explanation:

When providing coordination numbers and formulas for various coordination compounds, we first need to understand that the coordination number is the number of ligand atoms that are bound to the central metal ion in a coordination complex.

  • (a) [Co(CO3)3]³-: Carbonate (CO32-) is bidentate, so the coordination number for cobalt (Co) is six.
  • (b) [Cu(NH3)4]²+: Each ammonia (NH3) ligand connects at one point, giving copper (Cu) a coordination number of four.
  • (c) [Co(NH3)4Br2]SO4 : This cobalt (Co) complex has ammonia and bromine ligands, adding up to a coordination number of six.
  • (d) [Pt(NH3)4][PtCl4]: The first platinum (Pt) has a coordination number of four with ammonia, while the second Pt in the anionic part is surrounded by chlorides with coordination number four.
  • (e) [Cr(en)3](NO3)3: With three ethylenediamine (en) ligands, each bidentate, chromium (Cr) has a coordination number of six.
  • (f) [Pd(NH3)2Br₂]: Being square planar, palladium (Pd) has a coordination number of four.
  • (g) K3[Cu(CI)5]: Copper (Cu) is surrounded by five chloride ions, giving it a coordination number of five.
  • (h) [Zn(NH3)2Cl2]: Zinc (Zn) is coordinated by two ammonia and two chloride ligands, which results in a coordination number of four.
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