Question

Order the following molecules from least to most oxidized, based on the marked carbon atom:

a) CH₃CH₂OH (Ethanol) - Least oxidized
b) CH₃CHOHCH₃ (Isopropanol)
c) CH₃COOH (Methanoic acid)
d) CH₃COCH₃ (Acetone) - Most oxidized

Answer 1

The order of the given molecules from least to most oxidized, based on the marked carbon atom, is ethanol, isopropanol, methanoic acid, and acetone.

Step-by-step explanation:

The order of the given molecules from least to most oxidized, based on the marked carbon atom, is:

1. CH₃CH₂OH (Ethanol) - Least oxidized
2. CH₃CHOHCH₃ (Isopropanol)
3. CH₃COOH (Methanoic acid)
4. CH₃COCH₃ (Acetone) - Most oxidized

Ethanol contains a primary alcohol functional group, which is the least oxidized. Isopropanol contains a secondary alcohol functional group and is more oxidized than ethanol.

Methanoic acid contains a carboxylic acid functional group and is more oxidized than isopropanol. Acetone contains a ketone functional group and is the most oxidized among the given molecules.