Final answer:
Based on the information provided, the empirical formula for the white solid formed from the reaction between xenon and fluorine is xenon difluoride (XeF2), which has a 1:2 ratio of xenon to fluorine atoms.
Step-by-step explanation:
To determine the empirical formula for the white solid formed in the reaction of xenon and fluorine, we can consider the information provided about similar compounds.
Xenon reacts with fluorine to form several different compounds including xenon difluoride (XeF2), xenon tetrafluoride (XeF4), and xenon hexafluoride (XeF6), depending on the stoichiometry of the reaction.
Since the empirical formula must be based on the simplest whole number ratio, and considering the choices provided, xenon difluoride (XeF2) is the correct empirical formula, with xenon and fluorine in a 1:2 ratio. The white solid formed is most likely xenon difluoride, making the answer (b) XeF2.