Final answer:
The complexes [Pt(NH₃)₄]Cl₂, [Co(en)₃]³⁺, [Cr(CO)₆], and [Cu(NH₃)₄]²⁺ have square planar, trigonal planar, octahedral, and square planar structures respectively. None of the complexes have cis or trans isomers, nor optical isomers.
The correct answer is none of all.
Step-by-step explanation:
Structures of Complexes and Isomers
a. [Pt(NH₃)₄]Cl₂
This complex has a square planar structure. There are no cis or trans isomers because all the ligands (NH₃) are the same and there is no geometric isomerism. There is also no optical isomerism.
b. [Co(en)₃]³⁺
This complex has a trigonal planar structure. There are no cis or trans isomers because all the ligands (en) are the same and there is no geometric isomerism. There is no chiral center, so there are no optical isomers.
c. [Cr(CO)₆]
This complex has an octahedral structure. There are no cis or trans isomers because all the ligands (CO) are the same and there is no geometric isomerism. There are no chiral centers, so there are no optical isomers.
d. [Cu(NH₃)₄]²⁺
This complex has a square planar structure. There are no cis or trans isomers because all the ligands (NH₃) are the same and there is no geometric isomerism. There is no chiral center, so there are no optical isomers.