Final answer:
The strongest oxidizing agent among VO₄³⁻, CrO₄²⁻, and MnO₄⁻ is MnO₄⁻ due to its highest oxidation state of +7. The correct option is (C).
Step-by-step explanation:
The strongest oxidizing agent among VO₄³⁻, CrO₄²⁻, and MnO₄⁻ is MnO₄⁻. This is because manganese in MnO₄⁻ is in its highest oxidation state of +7, which makes it highly electronegative and able to attract electrons from other species.
In comparison, vanadium in VO₄³⁻ is in its +5 oxidation state, while chromium in CrO₄²⁻ is in its +6 oxidation state. Therefore, MnO₄⁻ has a higher oxidizing ability than the other two.