Final answer:
To calculate the grams of deuterium in an 80,000-L swimming pool where deuterium is 0.0150% of natural hydrogen, we first find the mass of hydrogen in the pool and then calculate the mass of deuterium from this value, resulting in 1,320 g of deuterium.
Step-by-step explanation:
Calculating Grams of Deuterium in a Swimming Pool
The question asks us to calculate the number of grams of deuterium in an 80,000-L swimming pool, given that deuterium makes up 0.0150% of natural hydrogen. First, let's determine the mass of the hydrogen in the pool. Since water (H2O) is composed of hydrogen and oxygen, and hydrogen accounts for about 11% of the water's mass, we'll use this percentage to find the total mass of hydrogen. Assuming 1 L of water is approximately 1 kg, the pool contains 80,000 kg of water.
The mass of hydrogen in the pool can be calculated as follows:
Mass of hydrogen = 0.11 * Total mass of water = 0.11 * 80,000 kg = 8,800 kg
Since deuterium is 0.0150% of this hydrogen, we can find the mass of deuterium:
Mass of deuterium = 0.0150% * Mass of hydrogen = 0.000150 * 8,800 kg = 1.32 kg
Now, converting this mass to grams (since 1 kg = 1,000 g):
Mass of deuterium in grams = 1.32 kg * 1,000 g/kg = 1,320 g
Therefore, the mass of deuterium in the swimming pool is 1,320 grams, which is not one of the answer choices provided, indicating there may be an error in the question or the answer choices.