Question

Use the Heisenberg uncertainty principle to calculate the uncertainty in energy for a corresponding time interval of 10⁻⁴³s

a)2×10³³J
b)5×10⁻²⁰J
c)1×10¹⁹J
d)4×10⁻³³J

Answer 1

The uncertainty in energy for a time interval of 10^-43 s can be calculated using the Heisenberg uncertainty principle. The uncertainty in energy is approximately 1 x 10^19 J.

Step-by-step explanation:

The Heisenberg uncertainty principle states that there is a limit to how precisely certain pairs of physical properties, such as position and momentum, can be known simultaneously.

One form of the uncertainty principle is given by the equation ΔEΔt ≥ ħ/2π, where ΔE represents the uncertainty in energy and Δt represents the uncertainty in time.

To calculate the uncertainty in energy for a corresponding time interval of 10-43 s, we can use the equation ΔEΔt ≥ ħ/2π. P

lugging in the values Δt = 10-43 s and ħ = 6.626 x 10-34 J·s, we can solve for ΔE.

ΔE = ħ/(2πΔt) = (6.626 x 10-34 J·s)/(2π(10-43 s)) ≈ 1 x 1019 J