Question

The primary decay mode for the negative pion is π−→μ−+vμ

What is the energy release in MeV in this decay?

a) mπ−mμ
b) mπ−mμ−mνμ
c) mπ−c²−mμc²
d) mπ-c²−mμc²−mνμc²

Answer 1

The energy release in the decay is the difference between the mass of the negative pion and the mass of the muon.

Step-by-step explanation:

The energy release in the decay of a negative pion, π-, into a muon, μ-, and a muon-neutrino, vμ, can be calculated using the equation: energy release = mass of the negative pion - mass of the muon.

Therefore, the correct answer is option a) mπ--mμ, which represents the energy release in MeV in this decay.