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What is the uncertainty in the energy released in the decay of a π⁰due to its short lifetime?

a) ℏ/τ
​b) ℏ/2τ
c) ℏ/√τ
​d) ℏ/τ²


1 Answer

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Final answer:

The uncertainty in the energy released in the decay of a π⁰ due to its short lifetime can be determined using theHeisenberg uncertainty principle. It is given by ℏ/τ.

Step-by-step explanation:

The uncertainty in the energy released in the decay of a π⁰ due to its short lifetime can be determined using the Heisenberg uncertainty principle. The energy-time uncertainty relation in quantum mechanics states that the uncertainty in the energy (ΔE) is inversely proportional to the uncertainty in time (Δt). Mathematically, ΔE × Δt ≥ ħ/2, where ħ is the reduced Planck's constant.

Since the π⁰ particle has a short lifetime (denoted by τ), we can express the uncertainty in time as τ. Therefore, the uncertainty in energy (ΔE) can be represented as ħ/τ. Hence, the correct option is (a) ℏ/τ.

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