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Show that the activity of the 14C in 1.00 g of 12C found in living tissue is 0.250 Bq.

a) True
b) False

User Yog Guru
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1 Answer

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Final answer:

The question on radioactive decay requires calculating the activity of 14C in carbon from living tissue using the half-life and the abundance of the isotope.

Step-by-step explanation:

The question is asking to show whether the statement about the activity of 14C in 1.00 g of 12C found in living tissue being 0.250 Bq is true or false. To calculate the activity (R) of a radioactive isotope, the formula R = (0.693 * N) / T1/2 is used, where N is the number of nuclei and T1/2 is the half-life of the isotope. Using the given abundance of 14C in living tissue (1.3 x 10-12 of the carbon content), we find the number of 14C nuclei in 1.00 g of 12C and use the known half-life of 14C (5730 years) to calculate the decay activity in Becquerels (Bq).

User Martin Lie
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