Question

What is the length of a side of a cube with a mass of 1.0 kg and a density of nuclear matter, assuming the density is (2.3 times 10¹⁷ , {kg/m}³)?

a) (1.42 times 10⁻⁷) m
b) (2.56 times 10⁻⁸) m
c) (3.21 times 10⁻⁹) m
d) (4.18 times 10⁻¹⁰) m

Answer 1

To find the length of a side of a cube with a mass of 1.0 kg and a density of nuclear matter, we can use the equation Density = mass / volume. By rearranging the equation and substituting the given values, we can calculate the length of a side of the cube to be approximately 3.21x10^-9 m.

Step-by-step explanation:

To find the length of a side of a cube with a mass of 1.0 kg and a density of nuclear matter, we can use the equation:

Density = mass / volume

The density of nuclear matter is given as 2.3x10^17 kg/m^3. We can rearrange the equation to solve for volume:

Volume = mass / density = 1.0 kg / 2.3x10^17 kg/m^3

Finally, we can calculate the length of a side of the cube by taking the cube root of the volume:

Length of side = cube root of volume

By substituting the values into the equation, we find that the length of a side of the cube is approximately 3.21x10^-9 m. Therefore, the correct answer is c) (3.21 times 10^-9) m.