Final answer:
The energy released in the β+ decay of 22Na can be calculated using the equation E = Δmc², where Δm is the change in mass. The mass of 22Na is 21.994434 u and the mass of 22Ne is 21.991383 u. The energy released is 2.744 × 10^-13 J.
Step-by-step explanation:
In the case of β+ decay, a positron (β+) is emitted from the nucleus, resulting in a decrease in the atomic number by 1 but an unchanged mass number. The energy released in this decay can be calculated using the equation E = Δmc², where Δm is the change in mass and c is the speed of light.
To calculate the energy released in the β+ decay of 22Na, we need to find the change in mass. The mass of 22Na is 21.994434 u and the mass of 22Ne is 21.991383 u. The change in mass can be calculated as Δm = mass of 22Na - mass of 22Ne = 21.994434 u - 21.991383 u = 0.003051 u.
Using the equation E = Δmc² and the mass change Δm = 0.003051 u, we can calculate the energy released as E = (0.003051 u) * (2.998 × 10^8 m/s)² = 2.744 × 10^-13 J.