Final answer:
The magnitude of the angular momentum for an electron in the n = 1 state in the Bohr model is equal to h / (2 * pi), which was proposed by Bohr.
The correct answer is A.
Step-by-step explanation:
In the Bohr model of the hydrogen atom, the magnitude of the angular momentum for an electron in the n = 1 state is given by the equation:
L = n * h / (2 * pi),
where L is the magnitude of the angular momentum, n is the quantum number, h is Planck's constant, and pi is a mathematical constant.
In this case, for the n = 1 state, the quantum number is 1, so the magnitude of the angular momentum is:
L = 1 * h / (2 * pi) = h / (2 * pi).
Bohr proposed that the magnitude of the angular momentum for an electron in the n = 1 state is h / (2 * pi). Comparing this to the calculated value, we can see that the answer is a) It is equal to Bohr's proposed value.