Final answer:
The parent nuclide in β- decay producing 90Y is 90Sr (Strontium-90), which undergoes β- decay by emitting an electron to become 90Y.
Step-by-step explanation:
The parent nuclide in β- decay producing 90Y is a major waste product of reactors, has chemistry similar to calcium, and can concentrate in bones if ingested. This parent nuclide is 90Sr (Strontium-90). When 90Sr undergoes β- decay, it turns into 90Y by emitting an electron (beta particle). This can be represented by the nuclear equation:
^{90}_{38}Sr → ^{90}_{39}Y + e^{-} + ¯\\u_{e}
The e^{-} represents the beta particle (electron) and ¯\\u_{e} represents the antineutrino.