90.9k views
3 votes
If a hydrogen atom is in the (n=4) state, how much energy is needed to ionize it?

a) (13.6 , {eV})
b) (2.55 , {eV})
c) (5.85 , {eV})
d) (8.32 , {eV})

1 Answer

0 votes

Final Answer:

The energy required to ionize a hydrogen atom from its nth energy level (n=4, in this case) can be calculated using the ionization energy formula
\[ E_{\text{ionization}} = -13.6 eV ×
\left((1)/(n^2)\right). If a hydrogen atom is in the (n=4) state, the much energy is needed to ionize it is 0.85 eV. Therefore, none of the provided options match the correct value.

Step-by-step explanation:

The energy required to ionize a hydrogen atom from its nth energy level (n=4, in this case) can be calculated using the ionization energy formula:


\[ E_{\text{ionization}} = -13.6 eV ×
\left((1)/(n^2)\right)

Substitute n=4 into the formula:


\[ E_{\text{ionization}} = -13.6 eV ×
\left((1)/(4^2)\right)


\[ E_{\text{ionization}} = -13.6 eV ×
\left((1)/(16)\right)


\[ E_{\text{ionization}} = -13.6 eV × 0.0625


\[ E_{\text{ionization}} = -0.85 eV

Since ionization energy is a positive quantity, the absolute value is taken:


\[ E_{\text{ionization}} = 0.85 eV

If a hydrogen atom is in the (n=4) state, the much energy is needed to ionize it is 0.85 eV.

Therefore, none of the provided options match the correct value.

User Sushmit Patil
by
8.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.