Question

A singly ionized helium ion ((He^+)) has only one electron. What is the ion's radius in the ground state compared to the Bohr radius of a hydrogen atom?

a) Smaller
b) Larger
c) Equal
d) Cannot be determined

Answer 1

a) Smaller

The radius of a singly ionized helium ion (He+) in the ground state is smaller compared to the Bohr radius of a hydrogen atom.

Step-by-step explanation:

The singly ionized helium ion (He+) has only one electron. In the ground state, the radius of the He+ ion is smaller compared to the Bohr radius of a hydrogen atom.

The Bohr radius of a hydrogen atom is approximately 0.529 angstroms (or 0.053 nm). The radius of the He+ ion can be determined using the equation for the Bohr radius:

r = rB x Z / 2

where

r is the radius of the ion

rB is the Bohr radius

Z is the atomic number

Since Z for He+ is 2, the radius of the He+ ion is:

r = 0.529 x 2 / 2 = 0.529 angstroms (or 0.053 nm).