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What is the magnitude of the angular momentum for an l=1 electron?

a) ℏ
b) 2ℏ
c) 3ℏ
d) 4ℏ

User Olsgaard
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1 Answer

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Final answer:

The magnitude of the angular momentum for an l=1 electron is ħ. This value is calculated using the formula L = √(l(l+1))ħ and simplifying for l=1.

Step-by-step explanation:

The magnitude of the angular momentum for an l=1 electron can be calculated using the formula L = √(l(l+1))ħ, where ħ is the reduced Planck's constant. For an electron with an angular momentum quantum number l of 1, the magnitude of its angular momentum is L = √(1(1+1))ħ = √2ħ.

This simplifies to L = √2 × (ħ/2√2) = ħ. Therefore, the correct answer is (a) ħ. The quantization of angular momentum was first recognized by Bohr in his model of the hydrogen atom.

User Zarkone
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