Answer:
778.4°C
Step-by-step explanation:
I = 700
R = 6x10⁻⁴
we first calculate the rate of heat that is being transferred by the current
q = I²R
q = 700²(6x10⁻⁴)
= 490000x0.0006
= 294 W/M
we calculate the surface temperature
Ts = T∞ +

Ts =



The surface temperature is therefore 778.4°C if the cable is bare