Question

What is the effective accelerating potential for electrons at the Stanford Linear Accelerator if γ = (1.00 × 10⁵) for them?

a) 0.01 TV
b) 0.1 TV
c) 1.0 TV
d) 10.0 TV

Answer 1

The effective accelerating potential for electrons at the Stanford Linear Accelerator is 0.01 TV (teravolt).

Step-by-step explanation:

To find the effective accelerating potential for electrons at the Stanford Linear Accelerator, we can use the equation:

V = γmc²/q

Where V is the accelerating potential, γ is the Lorentz factor, m is the mass of the electron, c is the speed of light, and q is the charge of the electron.

Given γ = 1.00 × 10⁵, we can substitute the values into the equation:

V = (1.00 × 10⁵)(9.11 × 10⁻³¹ kg)(3.00 × 10⁸ m/s)²/(1.60 × 10⁻¹⁹ C)

Calculating the expression gives us V ≈ 0.01 TV.

Therefore, the effective accelerating potential for electrons at the Stanford Linear Accelerator is 0.01 TV (teravolt).