Question

Find the momentum of a helium nucleus having a mass of 6.68×10^–27 kg that is moving at 0.200c.

a) 1.34 × 10^{–27} kg·m/s

b) 2.68 × 10^{–27 }kg·m/s

c) 5.36 × 10^{–27 }kg·m/s

d) 6.68 × 10^{–27} kg·m/s

Answer 1

The momentum of a helium nucleus with a mass of 6.68 x 10^-27 kg and moving at 0.200c is 4.008 x 10^-19 kg·m/s.

Step-by-step explanation:

To find the momentum of a helium nucleus, we can use the equation:

momentum = mass x velocity

Given that the mass of the helium nucleus is 6.68 x 10-27 kg and it is moving at 0.200c, we can substitute these values into the equation:

momentum = (6.68 x 10-27 kg) x (0.200c)

Since c represents the speed of light, which is approximately 3 x 108 m/s, we can calculate the momentum:

momentum = (6.68 x 10-27) x (0.200 x 3 x 108) kg·m/s

Simplifying the equation:

momentum = (6.68 x 10-27) x (0.600 x 108) kg·m/s

momentum = 4.008 x 10-19 kg·m/s

Therefore, the momentum of the helium nucleus is 4.008 x 10-19 kg·m/s. Option d) 4.008 x 10-19 kg·m/s is the correct answer.