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What is the velocity of an electron that has a momentum of (3.04 × 10⁻²¹ kg⋅ {m/s})? Note that you must calculate the velocity to at least four digits to see the difference from (c).

a) (3.04 × 10⁻²¹ kg ⋅ {m/s})

b) (c - 3.04 × 10⁻²¹ kg ⋅ {m/s})

c) (c + 3.04 × 10⁻²¹ kg ⋅ {m/s})

d) (c × (1 - (3.04 × 10⁻²¹)²)^{0.5})

User Yiwei
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1 Answer

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Final answer:

To find the velocity of an electron with a given momentum of 3.04 x 10^-21 kg-m/s, divide the momentum by the mass of the electron (9.11 x 10^-31 kg), resulting in a velocity of approximately 3.34 x 10^7 m/s, which is much less than the speed of light, c.

Step-by-step explanation:

The velocity of an electron that has a momentum of 3.04 × 10⁻²¹ kg·m/s can be calculated using the formula for momentum, p = mv, where p is momentum, m is mass, and v is velocity. The mass of an electron is 9.11 × 10⁻³¹ kg. Therefore, the velocity v can be found by rearranging the formula to v = p/m. Plugging in the given momentum and the mass of the electron, we calculate the velocity to be:

v = (3.04 × 10⁻²¹ kg·m/s) / (9.11 × 10⁻³¹ kg)

Velocity of the electron ≈ 3.34 × 10⁷ m/s, to four significant figures.

To find the velocity of an electron with a given momentum, we can use the equation:

p = mv

Where p represents the momentum, m is the mass of the electron, and v is the velocity. Rearranging the equation to solve for velocity, we get:

v = p/m

Plugging in the values, we have:

v = (3.04 × 10-21 kg·m/s) / (9.11 × 10-31 kg)

Calculating this expression gives the velocity of the electron, which is approximately 3.346 × 109 m/s (to at least four digits).

This velocity is significantly less than the speed of light c, which is approximately 3.00 × 10⁸ m/s.

User Steve Dunlop
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