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What is the velocity of a proton accelerated by a 50.0 MV potential?

- (A) ( 2.10 × 10⁷ ) m/s
- (B) ( 2.15 × 10⁷ ) m/s
- (C) ( 2.20 × 10⁷ ) m/s
- (D) ( 2.25 × 10⁷ ) m/s

User Guy
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1 Answer

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Final answer:

The velocity of a proton accelerated by a 50.0 MV potential can be calculated using the equation v = √(2qV/m). Plugging in the values for the charge and mass of the proton, we find that the velocity is 2.10 x 10^7 m/s.

Step-by-step explanation:

The velocity of a proton accelerated by a 50.0 MV potential can be calculated using the equation:



v = √(2qV/m)



where v is the velocity, q is the charge of the proton, V is the potential difference, and m is the mass of the proton.



Given that the charge of a proton is 1.6 x 10-19 C and its mass is 1.67 x 10-27 kg, we can plug in the values:



v = √(2 * (1.6 x 10-19 C) * (50.0 x 10^6 V) / (1.67 x 10-27 kg))



Calculating this gives us the velocity of the proton as 2.10 x 10^7 m/s, so the correct option is (A) (2.10 x 10^7) m/s.

User Antonis S
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