Question

What is the separation between two slits for which 610-nm orange light has its first maximum at an angle of 30.0º?

a) 1.22 μm
b) 0.61 μm
c) 2.44 μm
d) 3.05 μm

Answer 1

The separation between two slits for which 610-nm orange light has its first maximum at an angle of 30.0° is 1.22 μm.

Step-by-step explanation:

To find the separation between two slits for which 610-nm orange light has its first maximum at an angle of 30.0°, we can use the equation for the angle of the first maximum in the double-slit interference pattern:

sin(θ) = λ / d

Where θ is the angle, λ is the wavelength of light, and d is the slit separation.

Rearranging the equation, we find: d = λ / sin(θ). Plugging in the values: d = 610 nm / sin(30.0°).

Calculating:

d = 610 nm / 0.5 = 1.22 μm

The separation between two slits for which 610-nm orange light has its first maximum at an angle of 30.0° is 1.22 μm.