Final answer:
The young woman with a 10.0% ability to accommodate can see the closest object at approximately 18.2 cm. However, among the given options, the minimum clear vision distance would be 20.0 cm (option c).
Step-by-step explanation:
To determine the closest object a young woman with normal distant vision and a 10.0% ability to accommodate can see clearly, we use the formula relating the power of the eye and the image distance. The normal distant vision power is 50 diopters (D). When she accommodates, her eye power increases by 10%, making it 50 D + 10% of 50 D = 55 D.
Using the formula for lens power P = 1/f, where P is the power in diopters and f is the focal length in meters, we can find the closest point she can focus on. The focal length f is the inverse of the power P. Thus, f = 1/P. Substituting the accommodated power (55 D), we get f = 1/55 meters, which is approximately 0.0182 meters or 18.2 centimeters.
Therefore, the closest object she can see clearly is approximately 18.2 cm away, but among the provided options, 20.0 cm is the closest to this value and can be considered as the minimum distance she can clearly see an object.