Question

Find the distance between two slits that produce the first minimum for 410-nm violet light at an angle of 45.0º.

a) 0.82 μm
b) 1.23 μm
c) 0.41 μm
d) 2.05 μm

Answer 1

The distance between two slits that produce the first minimum for 410-nm violet light at an angle of 45.0º is approximately 0.82 μm.

Step-by-step explanation:

To find the distance between two slits that produce the first minimum for 410-nm violet light at an angle of 45.0º, we can use the formula for the position of the first minimum in a double-slit interference pattern:

d sin(θ) = mλ

Where d is the distance between the slits, θ is the angle, m is the order of the minimum (in this case, m = 1), and λ is the wavelength of the light.

Rearranging the formula, we have:

d = mλ / sin(θ)

Plugging in the values, d = (1)(410 nm) / sin(45.0º)

Calculating this, we get d ≈ 0.82 μm.