Final answer:
The maximum electric field strength created by a normal heartbeat, where a 4.00-mV potential difference is measured over 0.300 m of a person's chest, is 13.3 V/m, corresponding to option b as the correct answer.
Step-by-step explanation:
The question at hand requires us to calculate the maximum electric field strength that is created during a normal heartbeat, where a 4.00-mV potential difference is established across 0.300 m of a person’s chest.
To solve this, we use the formula for electric field strength (E), which is:
E = V/d
Where V is the potential difference and d is the distance over which the potential difference is measured. Plugging in the given values:
E = 4.00 mV / 0.300 m = 4.00×10⁻³ V / 0.300 m = 13.3 V/m
Hence, the maximum electric field strength created is 13.3 V/m, which corresponds to option b. It is important to choose the right option that matches the calculated value, in this case, option b is the correct option in the final answer.