101k views
0 votes
Approximately what is the smallest detail observable with a microscope that uses ultraviolet light of frequency 1.20x10^15 Hz?

a) 2.50x10^-7 meters
b) 1.50x10^-7 meters
c) 2.50x10^-8 meters
d) 1.50x10^-8 meters

1 Answer

4 votes

Final answer:

The smallest detail observable with a microscope that uses ultraviolet light of frequency 1.20 × 10¹5 Hz is approximately 2.50 × 10^-7 meters.

Step-by-step explanation:

The smallest detail observable with a microscope that uses ultraviolet light of frequency 1.20 × 10¹5 Hz can be determined using the formula:

Smallest Detail = λ / 2

Where λ represents the wavelength of the light. The wavelength can be found using the formula:

λ = c / f

Where c is the speed of light and f is the frequency of the ultraviolet light.

Given that c is approximately 3.00 × 10^8 meters per second and f is 1.20 × 10^15 Hz, we can substitute these values into the equation:

λ = (3.00 × 10^8 m/s) / (1.20 × 10^15 Hz)

Simplifying this expression, we find that the wavelength is approximately 2.50 × 10^-7 meters. Therefore, the smallest detail observable with the microscope is approximately half of this value, giving us an answer of a) 2.50 × 10^-7 meters.

User Windupurnomo
by
8.2k points