Question

A severely myopic patient has a far point of 5.00 cm. By how many diopters should the power of his eye be reduced in laser vision correction to obtain normal distant vision for him?

a) 5.00 D
b) 10.00 D
c) 2.00 D
d) 20.00 D

Answer 1

To obtain normal distant vision, the power of the eye needs to be reduced by 30.00 D.

Step-by-step explanation:

To calculate the amount the power of the severely myopic patient's eye needs to be reduced in laser vision correction to obtain normal distant vision, we need to find the difference between the power of the patient's eye and the power for normal distant vision. The power for normal distant vision is 50.0 D. The power of the patient's eye can be calculated using the formula:

Power of the eye = 1 / Far point

where Far point is the farthest point at which the patient can clearly see objects. In this case, the far point is given as 5.00 cm. Substituting this value into the formula:

Power of the eye = 1 / 0.05 m = 20.00 D

To obtain normal distant vision, the power of the patient's eye needs to be reduced by:

Power reduction = Power of the eye - Power for normal distant vision

Power reduction = 20.00 D - 50.0 D = -30.00 D

The power needs to be reduced by -30.00 D, which is equivalent to 30.00 D.