Question

The power of a physician’s eyes is 53.0 D while examining a patient. How far from her eyes is the feature being examined?

a) 0.189 m
b) 0.212 m
c) 0.178 m
d) 0.200 m

Answer 1

The feature being examined is 0.0189 meters or 18.9 cm away from the physician's eyes.

Step-by-step explanation:

The power of a physician's eyes is 53.0 D while examining a patient. In optics, power is measured in diopters (D). The power of an eye can be calculated using the formula:

Power (P) = 1/f,

where f is the focal length of the eye in meters. Rearranging the formula, we get:

f = 1/P.

Given that the power of the physician's eyes is 53.0 D, we can substitute this value into the formula to find the focal length:

f = 1/53.0 = 0.0189 m.

The feature being examined would be located at the focal point of the physician's eyes. Therefore, the feature is 0.0189 meters or 18.9 cm away from the physician's eyes.