Final answer:
The Hall voltage produced by a 0.200-T field applied across a 2.60-cm-diameter aorta with blood velocity at 60.0 cm/s is calculated to be 3.12 mV, which is not among the given options.
Step-by-step explanation:
The subject of this question concerns the concept of Hall voltage, which is relevant to Physics in the context of electromagnetism and fluid dynamics. To determine the Hall voltage produced by a magnetic field when blood is moving through an aorta, we can use the following relationship:
VH = B * v * d
Where:
- B is the magnetic field strength, in teslas (T).
- v is the velocity of the blood, in meters per second (m/s).
- d is the diameter of the aorta, in meters (m).
Given values:
- B = 0.200 T
- v = 60.0 cm/s (which is 0.600 m/s)
- d = 2.60 cm in diameter; the radius is half of that, so r = 1.30 cm or 0.013 m (since the voltage is developed across the diameter, we use the full diameter in the calculation)
The formula calculates the Hall voltage as follows:
VH = 0.200 T * 0.600 m/s * 0.026 m = 0.00312 V or 3.12 mV
None of the provided answer options (a) 0.15 mV, (b) 0.30 mV, (c) 0.45 mV, or (d) 0.60 mV are correct. The correct answer is 3.12 mV.