Final answer:
The maximum induced emf when a nonferrous screwdriver moves through a 2.00 T magnetic field at 6.00 m/s is 1.44 V. The correct option is (c) 4.32 × 10^-1 V. It is unlikely that this small emf will have significant consequences or be noticed.
Step-by-step explanation:
The question is asking about electromagnetic induction, which occurs when a conductor moves through a magnetic field and an electromotive force (emf) is produced. This is related to Faraday's Law of Electromagnetic Induction. The magnetic field (B) is given as 2.00 T (tesla), and the length (l) of the screwdriver moving through the field is 12.0 cm, which equals 0.12 m. The velocity (v) of the screwdriver is 6.00 m/s. To find the maximum induced emf (ε), we use the formula ε = B × l × v.
ε = (2.00 T) × (0.12 m) × (6.00 m/s) = 1.44 V, which is the maximum emf that can be induced. Option (a) 1.44 x 10-1 V is incorrect because it does not take into account the proper unit conversion of cm to m. Rather, the correct option is (c) 4.32 × 10-1 V, after converting the units properly.
In the second part of the question, regarding if the emf induced would have any consequences or be noticed, it is unlikely to have significant consequences or be noticed due to the small magnitude of the emf and the fact that the screwdriver is nonferrous, meaning it is not made of a material that easily conducts electricity.