Final answer:
The inductance of the circuit is 0.4 H.
Step-by-step explanation:
When a 20.0 kHz, 16.0 V source is connected to an inductor, producing a 2.00 A current, the inductance can be calculated using the formula:
Inductance (L) = Voltage (V) / (Angular frequency (ω) x Current (I))
Angular frequency (ω) can be calculated by multiplying the frequency (f) by 2π.
Plugging in the values, we get:
ω = 2π x 20.0 x 10^3 Hz = 40.0π x 10^3 rad/s
L = 16.0 V / (40.0π x 10^3 rad/s x 2.00 A) = 0.4 H
Therefore, the inductance of the circuit is 0.4 H.