Final answer:
Three time constants after the circuit is completed, approximately 95% of the final current would be flowing through the inductor in an RL circuit, which is not listed among the provided options.
Step-by-step explanation:
The question is asking for the percentage of the final current flowing through an inductor L in series with a resistor R, three time constants (RL circuit) after the circuit has been completed. In an RL circuit, the time constant (τ = L/R) is the time taken for the current to reach approximately 63.2% of its final value.
After three time constants, the current flowing through the circuit would have reached about 95% of its final value (since (1 - e-3) ≈ 0.95). Therefore, the answer is 95% of the final current, which isn't one of the provided options.
The percentage of the final current (I0) that flows through an inductor (L) in series with a resistor (R), three time constants after the circuit is completed can be calculated using the formula:
IL = I0 × (1 - e-3τ)
Where τ is the time constant of the circuit, which is equal to L/R. The time constant can be found by dividing the inductance (L) by the resistance (R).
In this case, the correct answer is option d) 27.2%.