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For a supply of inductors ranging from 1.00 nH to 10.0 H and resistors ranging from 0.100 Ω to 1.00 MΩ, what is the range of characteristic RL time constants you can produce by connecting a single resistor to a single inductor?

a) 1.00 ns to 1.00 s
b) 10.0 ns to 1.00 ks
c) 1.00 µs to 10.0 ks
d) 10.0 µs to 100.0 ks

User Oystein
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1 Answer

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Final answer:

The range of characteristic RL time constants that can be produced by connecting a single resistor to a single inductor is from 1.00 ns to 1.00 s. Therefore, the correct answer is a) 1.00 ns to 1.00 s.

Step-by-step explanation:

The characteristic RL time constant of a circuit is given by the product of the resistance (R) and the inductance (L). To find the range of characteristic RL time constants that can be produced by connecting a single resistor to a single inductor, we need to consider the minimum and maximum values of both components.

Given that the inductors range from 1.00 nH to 10.0 H, and the resistors range from 0.100 Ω to 1.00 MΩ, we can calculate the range as follows:

The minimum RL time constant is obtained by connecting the minimum resistor (0.100 Ω) to the maximum inductor (10.0 H), which gives 0.100 Ω * 10.0 H = 1.00 s.
The maximum RL time constant is obtained by connecting the maximum resistor (1.00 MΩ) to the minimum inductor (1.00 nH), which gives 1.00 MΩ * 1.00 nH = 1.00 ns.
Therefore, the range of characteristic RL time constants you can produce by connecting a single resistor to a single inductor is from 1.00 ns to 1.00 s.

User CoreyStup
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