Question

At what angular velocity in rpm will the peak voltage of a generator be 480 V, if its 500-turn, 8.00 cm diameter coil rotates in a 0.250 T field?

a) 1200 rpm
b) 1800 rpm
c) 2400 rpm
d) 3000 rpm

Answer 1

To find the angular velocity in rpm at which the peak voltage of the generator is 480 V, we can use the formula Vpeak = NABω. Solving for ω yields an angular velocity of 1200 rpm.

Step-by-step explanation:

To find the angular velocity in rpm at which the peak voltage of the generator is 480 V, we can use the formula:

Vpeak = NABω

Where N is the number of turns in the coil (500), A is the area of the coil (πr^2), B is the magnetic field (0.250 T), and ω is the angular velocity.

Using the given information, we can solve for ω:

Vpeak = 480 V

N = 500 turns

A = π(0.08 m)^2 = 0.0201 m^2

B = 0.250 T

480 = 500 * 0.0201 * 0.250 * ω

ω = 1200 rpm

Therefore, the peak voltage of 480 V will be reached at an angular velocity of 1200 rpm.