Final answer:
The ratio of secondary turns in the new transformer compared with the old is 750:335. The ratio of new current output to old for the same power level is 335:750. The ratio of new line power loss to old, assuming the same resistance, is the square of the current ratio, which is (750/335)^2.
Step-by-step explanation:
The original question involves the concept of transformer windings and their effect on output voltage and current, as well as power loss in transmission lines with a given resistance. First, we identify the ratio of turns in the secondary compared to the old secondary for the changed transformer from 335 kV to 750 kV output.
(a) The ratio of turns is directly proportional to the ratio of the secondary voltage to the primary voltage. So, to find the ratio of the new secondary compared to the old secondary, the formula would be:
New voltage / Old voltage = 750 kV / 335 kV = 750:335
For (b), the power (P) is the product of voltage (V) and current (I), P = VI. For the same power level, the ratio of new current output to the old current output is the inverse of the voltage ratio:
Old voltage / New voltage = 335 kV / 750 kV,
which simplifies to 335:750.
(c) The power loss (Ploss) in a resistor (like the transmission line with resistance R) is given by Ploss = I^2R. If the resistance remains the same, the ratio of new power loss to the old power loss will be the square of the current ratio. Thus, the ratio of new line power loss to old is:
(Old current / New current)^2 = (750 / 335)^2