Question

Two coils demonstrate Faraday’s law of induction. If a 5.00 A current is switched off in one coil in 1.00 ms, inducing a 9.00 V emf in the other, what is their mutual inductance?

a) 0.045 H
b) 0.009 H
c) 0.900 H
d) 4.500 H

Answer 1

The mutual inductance between the two coils is 0.045 H.

Step-by-step explanation:

According to Faraday's law of induction, the induced EMF in a coil is directly proportional to the rate of change of current in the neighboring coil and their mutual inductance. In this case, the rate of change of current is 5.00 A in 1.00 ms, and the induced EMF is 9.00 V. To find the mutual inductance, we can use the formula:

EMF = M * (ΔI/Δt)

where EMF is the induced EMF, M is the mutual inductance, ΔI is the change in current, and Δt is the change in time.

Substituting the given values into the formula, we have:

9.00 V = M * (5.00 A/1.00 ms)

Simplifying, we find that the mutual inductance M = 0.045 H (henries).