Question

Find the current through a loop needed to create a maximum torque of 9.00 N⋅m. The loop has 50 square turns that are 15.0 cm on a side and is in a uniform 0.800-T magnetic field.

a) 3.00 A
b) 4.50 A
c) 6.00 A
d) 7.50 A

Answer 1

The current through the loop needed to create a maximum torque of 9.00 N⋅m is 6.00 A.

Step-by-step explanation:

To find the current through a loop needed to create a maximum torque, we can use the equation T = NIA sin(theta), where T is the torque, N is the number of turns, I is the current, A is the area of the loop, and theta is the angle between the magnetic field and the loop's normal. In this case, the loop has 50 square turns that are 15.0 cm on a side, and the magnetic field is 0.800 T.

The area of the loop is given by A = (side length)^2, so A = (0.15 m)^2 = 0.0225 m^2.

Substituting the values into the equation, 9.00 Nm = (50)(I)(0.0225 m^2)(0.800 T) sin(theta).

Solving for I, we get I = 6.00 A. Therefore, the current through the loop needed to create a maximum torque of 9.00 Nm is 6.00 A.