Final answer:
The force on a 100-m section of a DC power line in a magnetic field can be calculated using the formula involving current, length of wire, magnetic field strength, and the angle between the current and field. The calculated force is 2.50 N, although it does not match the provided options.
Step-by-step explanation:
To calculate the force exerted on a section of a power line by a magnetic field, we can use the formula F = I * L * B * sin(\(\theta\)), where I is the current, L is the length of the wire, B is the magnetic field strength, and \(\theta\) is the angle the current makes with the magnetic field.
In our case, the current I is 1000 A, the length of the wire L is 100 m, the magnetic field strength B is 5.00 \(\times\) 10-5 T, and the angle \(\theta\) is 30.0\(\degree\). Plugging these values into the formula, we get:
F = 1000 A * 100 m * 5.00 \(\times\) 10-5 T * sin(30.0\(\degree\))
F = 1000 * 100 * 5.00 \(\times\) 10-5 * 0.5
F = 2.50 N
Therefore, the force on a 100-m section of this line is 2.50 N, which appears to not match any of the provided options. There might be an error in the question's options or my interpretation.
Regarding practical concerns, such a force, if constantly applied, can cause stress on the power line's supports and structures. Regular maintenance and robust construction are necessary to ensure reliability and safety in the presence of these magnetic forces.