Question

How strong is the magnetic field inside a solenoid with 10,000 turns per meter that carries 20.0 A?

a) 1.6 × 10-2 T
b) 2.0 × 10-2 T
c) 4.0 × 10-2 TV
d) 5.0 × 10-2 T

Answer 1

The magnetic field inside a solenoid with 10,000 turns per meter carrying 20.0 A is 8.0 × 10-2 T.

Step-by-step explanation:

The magnetic field inside a solenoid can be calculated using the formula:

B = μ₀ * n * I

where B is the magnetic field, μ₀ is the permeability of free space (4π × 10-7 T·m/A), n is the number of turns per meter, and I is the current in amperes.

Plugging in the given values, we have:

B = (4π × 10-7 T·m/A) * (10,000 turns/m) * (20.0 A) = 8.0 × 10-2 T