Question

A large water main with a 2.50 m diameter has an average water velocity of 6.00 m/s. Find the Hall voltage produced if the pipe runs perpendicular to the Earth’s 5.00×10^−5 T magnetic field.

a) 0.75 V
b) 1.50 V
c) 2.25 V
d) 3.00 V

Answer 1

The Hall voltage produced is 7.50 V.

Step-by-step explanation:

The Hall voltage produced can be found using the formula:

VH = B * v * d

Where VH is the Hall voltage, B is the magnetic field strength, v is the water velocity, and d is the diameter of the water main.

Plugging in the given values, we have:

VH = (5.00 × 10-5 T) * (6.00 m/s) * (2.50 m)

Simplifying the calculation:

VH = 7.50 V

Therefore, the Hall voltage produced is 7.50 V.