Final answer:
The sensitivity of the galvanometer in the voltmeter with a 1.00-MΩ resistance on its 30.0-V scale is 30.0 μA.
Step-by-step explanation:
The sensitivity of a galvanometer is determined by the current required to produce a full-scale deflection on its scale. In this case, we have a voltmeter with a 1.00-MΩ resistance on its 30.0-V scale. To find the sensitivity, we can use Ohm's law (V = IR). Rearranging the formula, we have I = V/R. Plugging in the values, we get:
I = 30.0 V / 1.00 MΩ = 30.0 x 10^-6 A = 30.0 μA.