Final answer:
The largest resistance obtained by connecting a 36.0-Ω, a 50.0-Ω, and a 700-Ω resistor is 786.0 Ω in series, while the smallest is approximately 12 Ω in parallel.
Step-by-step explanation:
To find the largest and smallest resistances that can be obtained by connecting a 36.0-Ω, a 50.0-Ω, and a 700-Ω resistor together, we need to consider resistors in series and parallel configurations. For the largest resistance, all resistors are connected in a series configuration, which is simply the sum of all individual resistances:
36.0 Ω + 50.0 Ω + 700 Ω = 786.0 Ω
For the smallest resistance, all resistors are connected in a parallel configuration, which requires the reciprocal sum of the individual resistors' reciprocals:
The largest resistance you can obtain by connecting a 36.0-Ω, a 50.0-Ω, and a 700-Ω resistor together is equal to the sum of all the resistances.
Therefore, the largest resistance is 36.0 Ω + 50.0 Ω + 700.0 Ω = 786 Ω. On the other hand, the smallest resistance you can obtain is when all the resistors are connected in parallel. In this case, the smallest resistance is given by the reciprocal of the sum of the reciprocals of the resistances.
1/(1/36.0 + 1/50.0 + 1/700) Ω ≈ 12 Ω
Therefore, the largest resistance is 786 Ω and the smallest is approximately 12 Ω.