Final answer:
The output voltage of the Hall probe when placed in a 0.150-T field is 0.0750 µV.
Step-by-step explanation:
To find the output voltage of the Hall probe when placed in a 0.150-T field, we can use the equation:
Vout = Vcalibrated × Bout / Bcalibrated
where Vout is the output voltage, Vcalibrated is the voltage when placed in a calibrated field, Bout is the field the probe is placed in, and Bcalibrated is the calibrated field. Given that Vcalibrated = 1.00 µV, Bcalibrated = 2.00 T, and Bout = 0.150 T, we can substitute these values into the equation:
Vout = (1.00 µV) × (0.150 T) / (2.00 T) = 0.0750 µV
Therefore, the output voltage of the Hall probe when placed in a 0.150-T field is 0.0750 µV (option c).