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What is the resistance of ten 275-Ω resistors connected in series? (b) In parallel?

a. (a) 2750 Ω (b) 27.5 Ω
b. (a) 275 Ω (b) 2750 Ω
c. (a) 2750 Ω (b) 275 Ω
d. (a) 27.5 Ω (b) 2750 Ω

User Mohan
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1 Answer

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Final answer:

For ten 275-ohm resistors connected in series, the total resistance is 2750 ohms, and for the same resistors connected in parallel, the total resistance is 27.5 ohms.

Step-by-step explanation:

Calculating Resistance in Series and Parallel

Series Connection: When resistors are connected in series, the total resistance is the sum of all individual resistances. Hence, for ten 275-ohm resistors connected in series, we calculate the total resistance as follows:

  • Rtotal, series = R1 + R2 + ... + R10
  • Rtotal, series = 10 × 275Ω
  • Rtotal, series = 2750Ω

Parallel Connection: For resistors in parallel, the total resistance is found by taking the reciprocal of the sum of the reciprocals of each resistance. Thus, for ten 275-ohm resistors connected in parallel, the calculation is:

  • 1/Rtotal, parallel = 1/R1 + 1/R2 + ... + 1/R10
  • 1/Rtotal, parallel = 10 × (1/275Ω)
  • Rtotal, parallel = Ω / 10
  • Rtotal, parallel = 27.5Ω

Therefore, the correct answers are: (a) 2750Ω and (b) 27.5Ω.

User Shuyi
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